3.3.46 \(\int \frac {x}{\sqrt {a-b x^3} (2 (5+3 \sqrt {3}) a-b x^3)} \, dx\)

Optimal. Leaf size=324 \[ -\frac {\left (2-\sqrt {3}\right ) \tan ^{-1}\left (\frac {\sqrt [4]{3} \left (1+\sqrt {3}\right ) \sqrt [6]{a} \left (\sqrt [3]{a}-\sqrt [3]{b} x\right )}{\sqrt {2} \sqrt {a-b x^3}}\right )}{2 \sqrt {2} 3^{3/4} a^{5/6} b^{2/3}}-\frac {\left (2-\sqrt {3}\right ) \tan ^{-1}\left (\frac {\left (1-\sqrt {3}\right ) \sqrt {a-b x^3}}{\sqrt {2} 3^{3/4} \sqrt {a}}\right )}{3 \sqrt {2} 3^{3/4} a^{5/6} b^{2/3}}-\frac {\left (2-\sqrt {3}\right ) \tanh ^{-1}\left (\frac {\sqrt [4]{3} \left (1-\sqrt {3}\right ) \sqrt [6]{a} \left (\sqrt [3]{a}-\sqrt [3]{b} x\right )}{\sqrt {2} \sqrt {a-b x^3}}\right )}{6 \sqrt {2} \sqrt [4]{3} a^{5/6} b^{2/3}}-\frac {\left (2-\sqrt {3}\right ) \tanh ^{-1}\left (\frac {\sqrt [4]{3} \sqrt [6]{a} \left (\left (1+\sqrt {3}\right ) \sqrt [3]{a}+2 \sqrt [3]{b} x\right )}{\sqrt {2} \sqrt {a-b x^3}}\right )}{3 \sqrt {2} \sqrt [4]{3} a^{5/6} b^{2/3}} \]

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Rubi [A]  time = 0.07, antiderivative size = 324, normalized size of antiderivative = 1.00, number of steps used = 1, number of rules used = 1, integrand size = 35, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.029, Rules used = {487} \begin {gather*} -\frac {\left (2-\sqrt {3}\right ) \tan ^{-1}\left (\frac {\sqrt [4]{3} \left (1+\sqrt {3}\right ) \sqrt [6]{a} \left (\sqrt [3]{a}-\sqrt [3]{b} x\right )}{\sqrt {2} \sqrt {a-b x^3}}\right )}{2 \sqrt {2} 3^{3/4} a^{5/6} b^{2/3}}-\frac {\left (2-\sqrt {3}\right ) \tan ^{-1}\left (\frac {\left (1-\sqrt {3}\right ) \sqrt {a-b x^3}}{\sqrt {2} 3^{3/4} \sqrt {a}}\right )}{3 \sqrt {2} 3^{3/4} a^{5/6} b^{2/3}}-\frac {\left (2-\sqrt {3}\right ) \tanh ^{-1}\left (\frac {\sqrt [4]{3} \left (1-\sqrt {3}\right ) \sqrt [6]{a} \left (\sqrt [3]{a}-\sqrt [3]{b} x\right )}{\sqrt {2} \sqrt {a-b x^3}}\right )}{6 \sqrt {2} \sqrt [4]{3} a^{5/6} b^{2/3}}-\frac {\left (2-\sqrt {3}\right ) \tanh ^{-1}\left (\frac {\sqrt [4]{3} \sqrt [6]{a} \left (\left (1+\sqrt {3}\right ) \sqrt [3]{a}+2 \sqrt [3]{b} x\right )}{\sqrt {2} \sqrt {a-b x^3}}\right )}{3 \sqrt {2} \sqrt [4]{3} a^{5/6} b^{2/3}} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[x/(Sqrt[a - b*x^3]*(2*(5 + 3*Sqrt[3])*a - b*x^3)),x]

[Out]

-((2 - Sqrt[3])*ArcTan[(3^(1/4)*(1 + Sqrt[3])*a^(1/6)*(a^(1/3) - b^(1/3)*x))/(Sqrt[2]*Sqrt[a - b*x^3])])/(2*Sq
rt[2]*3^(3/4)*a^(5/6)*b^(2/3)) - ((2 - Sqrt[3])*ArcTan[((1 - Sqrt[3])*Sqrt[a - b*x^3])/(Sqrt[2]*3^(3/4)*Sqrt[a
])])/(3*Sqrt[2]*3^(3/4)*a^(5/6)*b^(2/3)) - ((2 - Sqrt[3])*ArcTanh[(3^(1/4)*(1 - Sqrt[3])*a^(1/6)*(a^(1/3) - b^
(1/3)*x))/(Sqrt[2]*Sqrt[a - b*x^3])])/(6*Sqrt[2]*3^(1/4)*a^(5/6)*b^(2/3)) - ((2 - Sqrt[3])*ArcTanh[(3^(1/4)*a^
(1/6)*((1 + Sqrt[3])*a^(1/3) + 2*b^(1/3)*x))/(Sqrt[2]*Sqrt[a - b*x^3])])/(3*Sqrt[2]*3^(1/4)*a^(5/6)*b^(2/3))

Rule 487

Int[(x_)/(Sqrt[(a_) + (b_.)*(x_)^3]*((c_) + (d_.)*(x_)^3)), x_Symbol] :> With[{q = Rt[b/a, 3], r = Simplify[(b
*c - 10*a*d)/(6*a*d)]}, -Simp[(q*(2 - r)*ArcTan[((1 - r)*Sqrt[a + b*x^3])/(Sqrt[2]*Rt[a, 2]*r^(3/2))])/(3*Sqrt
[2]*Rt[a, 2]*d*r^(3/2)), x] + (-Simp[(q*(2 - r)*ArcTan[(Rt[a, 2]*Sqrt[r]*(1 + r)*(1 + q*x))/(Sqrt[2]*Sqrt[a +
b*x^3])])/(2*Sqrt[2]*Rt[a, 2]*d*r^(3/2)), x] - Simp[(q*(2 - r)*ArcTanh[(Rt[a, 2]*Sqrt[r]*(1 + r - 2*q*x))/(Sqr
t[2]*Sqrt[a + b*x^3])])/(3*Sqrt[2]*Rt[a, 2]*d*Sqrt[r]), x] - Simp[(q*(2 - r)*ArcTanh[(Rt[a, 2]*(1 - r)*Sqrt[r]
*(1 + q*x))/(Sqrt[2]*Sqrt[a + b*x^3])])/(6*Sqrt[2]*Rt[a, 2]*d*Sqrt[r]), x])] /; FreeQ[{a, b, c, d}, x] && NeQ[
b*c - a*d, 0] && EqQ[b^2*c^2 - 20*a*b*c*d - 8*a^2*d^2, 0] && PosQ[a]

Rubi steps

\begin {align*} \int \frac {x}{\sqrt {a-b x^3} \left (2 \left (5+3 \sqrt {3}\right ) a-b x^3\right )} \, dx &=-\frac {\left (2-\sqrt {3}\right ) \tan ^{-1}\left (\frac {\sqrt [4]{3} \left (1+\sqrt {3}\right ) \sqrt [6]{a} \left (\sqrt [3]{a}-\sqrt [3]{b} x\right )}{\sqrt {2} \sqrt {a-b x^3}}\right )}{2 \sqrt {2} 3^{3/4} a^{5/6} b^{2/3}}-\frac {\left (2-\sqrt {3}\right ) \tan ^{-1}\left (\frac {\left (1-\sqrt {3}\right ) \sqrt {a-b x^3}}{\sqrt {2} 3^{3/4} \sqrt {a}}\right )}{3 \sqrt {2} 3^{3/4} a^{5/6} b^{2/3}}-\frac {\left (2-\sqrt {3}\right ) \tanh ^{-1}\left (\frac {\sqrt [4]{3} \left (1-\sqrt {3}\right ) \sqrt [6]{a} \left (\sqrt [3]{a}-\sqrt [3]{b} x\right )}{\sqrt {2} \sqrt {a-b x^3}}\right )}{6 \sqrt {2} \sqrt [4]{3} a^{5/6} b^{2/3}}-\frac {\left (2-\sqrt {3}\right ) \tanh ^{-1}\left (\frac {\sqrt [4]{3} \sqrt [6]{a} \left (\left (1+\sqrt {3}\right ) \sqrt [3]{a}+2 \sqrt [3]{b} x\right )}{\sqrt {2} \sqrt {a-b x^3}}\right )}{3 \sqrt {2} \sqrt [4]{3} a^{5/6} b^{2/3}}\\ \end {align*}

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Mathematica [C]  time = 0.08, size = 83, normalized size = 0.26 \begin {gather*} \frac {x^2 \sqrt {1-\frac {b x^3}{a}} F_1\left (\frac {2}{3};\frac {1}{2},1;\frac {5}{3};\frac {b x^3}{a},\frac {b x^3}{6 \sqrt {3} a+10 a}\right )}{\left (12 \sqrt {3} a+20 a\right ) \sqrt {a-b x^3}} \end {gather*}

Warning: Unable to verify antiderivative.

[In]

Integrate[x/(Sqrt[a - b*x^3]*(2*(5 + 3*Sqrt[3])*a - b*x^3)),x]

[Out]

(x^2*Sqrt[1 - (b*x^3)/a]*AppellF1[2/3, 1/2, 1, 5/3, (b*x^3)/a, (b*x^3)/(10*a + 6*Sqrt[3]*a)])/((20*a + 12*Sqrt
[3]*a)*Sqrt[a - b*x^3])

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IntegrateAlgebraic [F]  time = 31.26, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {x}{\sqrt {a-b x^3} \left (2 \left (5+3 \sqrt {3}\right ) a-b x^3\right )} \, dx \end {gather*}

Verification is not applicable to the result.

[In]

IntegrateAlgebraic[x/(Sqrt[a - b*x^3]*(2*(5 + 3*Sqrt[3])*a - b*x^3)),x]

[Out]

Defer[IntegrateAlgebraic][x/(Sqrt[a - b*x^3]*(2*(5 + 3*Sqrt[3])*a - b*x^3)), x]

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fricas [F(-2)]  time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Exception raised: TypeError} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x/(-b*x^3+2*a*(5+3*3^(1/2)))/(-b*x^3+a)^(1/2),x, algorithm="fricas")

[Out]

Exception raised: TypeError >>  Error detected within library code:   catdef: division by zero

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giac [F(-2)]  time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Exception raised: RuntimeError} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x/(-b*x^3+2*a*(5+3*3^(1/2)))/(-b*x^3+a)^(1/2),x, algorithm="giac")

[Out]

Exception raised: RuntimeError >> An error occurred running a Giac command:INPUT:sage2OUTPUT:index.cc index_m
operator + Error: Bad Argument Value

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maple [C]  time = 0.41, size = 509, normalized size = 1.57 \begin {gather*} \frac {i \left (a \,b^{2}\right )^{\frac {1}{3}} \sqrt {-\frac {i \left (2 x +\frac {i \sqrt {3}\, \left (a \,b^{2}\right )^{\frac {1}{3}}+\left (a \,b^{2}\right )^{\frac {1}{3}}}{b}\right ) b}{2 \left (a \,b^{2}\right )^{\frac {1}{3}}}}\, \sqrt {\frac {\left (x -\frac {\left (a \,b^{2}\right )^{\frac {1}{3}}}{b}\right ) b}{-3 \left (a \,b^{2}\right )^{\frac {1}{3}}-i \sqrt {3}\, \left (a \,b^{2}\right )^{\frac {1}{3}}}}\, \sqrt {\frac {i \left (2 x +\frac {-i \sqrt {3}\, \left (a \,b^{2}\right )^{\frac {1}{3}}+\left (a \,b^{2}\right )^{\frac {1}{3}}}{b}\right ) b}{\left (a \,b^{2}\right )^{\frac {1}{3}}}}\, \left (4 \sqrt {3}\, \RootOf \left (\textit {\_Z}^{3} b -6 \sqrt {3}\, a -10 a \right )^{2} b^{2}-6 \RootOf \left (\textit {\_Z}^{3} b -6 \sqrt {3}\, a -10 a \right )^{2} b^{2}+3 i \left (a \,b^{2}\right )^{\frac {1}{3}} \sqrt {3}\, \RootOf \left (\textit {\_Z}^{3} b -6 \sqrt {3}\, a -10 a \right ) b -6 i \left (a \,b^{2}\right )^{\frac {1}{3}} \RootOf \left (\textit {\_Z}^{3} b -6 \sqrt {3}\, a -10 a \right ) b -2 \sqrt {3}\, \left (a \,b^{2}\right )^{\frac {1}{3}} \RootOf \left (\textit {\_Z}^{3} b -6 \sqrt {3}\, a -10 a \right ) b +3 \left (a \,b^{2}\right )^{\frac {1}{3}} \RootOf \left (\textit {\_Z}^{3} b -6 \sqrt {3}\, a -10 a \right ) b -3 i \left (a \,b^{2}\right )^{\frac {2}{3}} \sqrt {3}+6 i \left (a \,b^{2}\right )^{\frac {2}{3}}-2 \sqrt {3}\, \left (a \,b^{2}\right )^{\frac {2}{3}}+3 \left (a \,b^{2}\right )^{\frac {2}{3}}\right ) \EllipticPi \left (\frac {\sqrt {3}\, \sqrt {-\frac {i \left (x +\frac {\left (a \,b^{2}\right )^{\frac {1}{3}}}{2 b}+\frac {i \sqrt {3}\, \left (a \,b^{2}\right )^{\frac {1}{3}}}{2 b}\right ) \sqrt {3}\, b}{\left (a \,b^{2}\right )^{\frac {1}{3}}}}}{3}, \frac {-2 i \sqrt {3}\, \left (a \,b^{2}\right )^{\frac {1}{3}} \RootOf \left (\textit {\_Z}^{3} b -6 \sqrt {3}\, a -10 a \right )^{2} b +4 i \left (a \,b^{2}\right )^{\frac {1}{3}} \RootOf \left (\textit {\_Z}^{3} b -6 \sqrt {3}\, a -10 a \right )^{2} b +i \sqrt {3}\, a b -2 i a b -2 \sqrt {3}\, a b +3 a b +i \sqrt {3}\, \left (a \,b^{2}\right )^{\frac {2}{3}} \RootOf \left (\textit {\_Z}^{3} b -6 \sqrt {3}\, a -10 a \right )-2 i \left (a \,b^{2}\right )^{\frac {2}{3}} \RootOf \left (\textit {\_Z}^{3} b -6 \sqrt {3}\, a -10 a \right )+2 \sqrt {3}\, \left (a \,b^{2}\right )^{\frac {2}{3}} \RootOf \left (\textit {\_Z}^{3} b -6 \sqrt {3}\, a -10 a \right )-3 \left (a \,b^{2}\right )^{\frac {2}{3}} \RootOf \left (\textit {\_Z}^{3} b -6 \sqrt {3}\, a -10 a \right )}{6 a b}, \sqrt {-\frac {i \sqrt {3}\, \left (a \,b^{2}\right )^{\frac {1}{3}}}{\left (-\frac {3 \left (a \,b^{2}\right )^{\frac {1}{3}}}{2 b}-\frac {i \sqrt {3}\, \left (a \,b^{2}\right )^{\frac {1}{3}}}{2 b}\right ) b}}\right )}{27 a \,b^{3} \sqrt {-b \,x^{3}+a}\, \RootOf \left (\textit {\_Z}^{3} b -6 \sqrt {3}\, a -10 a \right )} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x/(-b*x^3+2*a*(5+3*3^(1/2)))/(-b*x^3+a)^(1/2),x)

[Out]

1/27*I/b^3/a*2^(1/2)*sum(1/_alpha*(a*b^2)^(1/3)*(-1/2*I*(2*x+(I*3^(1/2)*(a*b^2)^(1/3)+(a*b^2)^(1/3))/b)/(a*b^2
)^(1/3)*b)^(1/2)*((x-(a*b^2)^(1/3)/b)/(-3*(a*b^2)^(1/3)-I*3^(1/2)*(a*b^2)^(1/3))*b)^(1/2)*(1/2*I*(2*x+(-I*3^(1
/2)*(a*b^2)^(1/3)+(a*b^2)^(1/3))/b)/(a*b^2)^(1/3)*b)^(1/2)/(-b*x^3+a)^(1/2)*(4*3^(1/2)*_alpha^2*b^2-6*_alpha^2
*b^2+3*I*(a*b^2)^(1/3)*3^(1/2)*_alpha*b-6*I*(a*b^2)^(1/3)*_alpha*b-2*3^(1/2)*(a*b^2)^(1/3)*_alpha*b+3*(a*b^2)^
(1/3)*_alpha*b-3*I*(a*b^2)^(2/3)*3^(1/2)+6*I*(a*b^2)^(2/3)-2*3^(1/2)*(a*b^2)^(2/3)+3*(a*b^2)^(2/3))*EllipticPi
(1/3*3^(1/2)*(-I*(x+1/2*(a*b^2)^(1/3)/b+1/2*I*3^(1/2)*(a*b^2)^(1/3)/b)*3^(1/2)/(a*b^2)^(1/3)*b)^(1/2),1/6*(-2*
I*3^(1/2)*(a*b^2)^(1/3)*_alpha^2*b+4*I*(a*b^2)^(1/3)*_alpha^2*b+I*3^(1/2)*a*b-2*I*a*b-2*3^(1/2)*a*b+3*a*b+I*3^
(1/2)*(a*b^2)^(2/3)*_alpha-2*I*(a*b^2)^(2/3)*_alpha+2*3^(1/2)*(a*b^2)^(2/3)*_alpha-3*(a*b^2)^(2/3)*_alpha)/a/b
,(-I*3^(1/2)*(a*b^2)^(1/3)/(-3/2*(a*b^2)^(1/3)/b-1/2*I*3^(1/2)*(a*b^2)^(1/3)/b)/b)^(1/2)),_alpha=RootOf(_Z^3*b
-6*3^(1/2)*a-10*a))

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maxima [F]  time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} -\int \frac {x}{{\left (b x^{3} - 2 \, a {\left (3 \, \sqrt {3} + 5\right )}\right )} \sqrt {-b x^{3} + a}}\,{d x} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x/(-b*x^3+2*a*(5+3*3^(1/2)))/(-b*x^3+a)^(1/2),x, algorithm="maxima")

[Out]

-integrate(x/((b*x^3 - 2*a*(3*sqrt(3) + 5))*sqrt(-b*x^3 + a)), x)

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mupad [F]  time = 0.00, size = -1, normalized size = -0.00 \begin {gather*} -\int \frac {x}{\sqrt {a-b\,x^3}\,\left (b\,x^3-2\,a\,\left (3\,\sqrt {3}+5\right )\right )} \,d x \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(-x/((a - b*x^3)^(1/2)*(b*x^3 - 2*a*(3*3^(1/2) + 5))),x)

[Out]

-int(x/((a - b*x^3)^(1/2)*(b*x^3 - 2*a*(3*3^(1/2) + 5))), x)

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sympy [F]  time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} - \int \frac {x}{- 6 \sqrt {3} a \sqrt {a - b x^{3}} - 10 a \sqrt {a - b x^{3}} + b x^{3} \sqrt {a - b x^{3}}}\, dx \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x/(-b*x**3+2*a*(5+3*3**(1/2)))/(-b*x**3+a)**(1/2),x)

[Out]

-Integral(x/(-6*sqrt(3)*a*sqrt(a - b*x**3) - 10*a*sqrt(a - b*x**3) + b*x**3*sqrt(a - b*x**3)), x)

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